2. A metal block has a dimension of 20 cm x 20 cm x 10 cm. When placed in anelectronic balance, it has a mass of 2.0 kg. What is the density of the rectangularblock?​

1. 2. A metal block has a dimension of 20 cm x 20 cm x 10 cm. When placed in anelectronic balance, it has a mass of 2.0 kg. What is the density of the rectangularblock?​

Jawaban:

2. Balok logam berukuran 20 cm x 20 cm x 10 cm. Saat ditempatkan di neraca elektronik, memiliki massa 2,0 kg. Berapa massa jenis balok

v balok = p.l.t

=20x20x10

=4000cm³

ρ=m/v

=20/4000

=5x10^-3 kg/cm³

2. A small car with mass of 1000 kg is moving eastward with velocity of 30m/s and big car with mass of 2000 kg is moving southward with velocity of 20 m/s.The magnitude of momentum after colliding is..

Penjelasan:

dik : m1 = 1000 kg

v1 = 30m/s

m2 = 2000 kg

v2 = 20 m/s

dit: momentum atau p.... ?

jawab:

karna tidak ada diketahui koefisien dan cuma momentum setelah tabrakan maka menggunakan hukum kekekalan momentum sehingga persamaan seperti ini

p = p'

(m1 x v1) + (m2 x v2) = p'

p' = (1000 x 30) + (2000 x -20)

p' = 30.000 - 40.000

p' = -10.000

jadi besarnya momentum adalah -10.000 atau 10.000... mohon maaf kalau ada yang salah

3. the mass of a bag of nuts is 215 g What is the mass of 10 bags of nuts in kilograms, kg?​

[tex] \frac{10 \: bags}{1 \: bag} \times 215 \: g = 2150 \: g = 2.15 \: kg[/tex]

4. A block of mass 5 kg initially at rest at the origin is acted on by a force along the positive X - direction represented by F= (20 +5x) N. Calculate the work done by the force during the displacement of the block from x=0 at x = 4mMakasih ^^" ​

Question:

A block of mass 5 kg initially at rest at the origin is acted on by a force along the positive X - direction represented by F= (20 +5x) N. Calculate the work done by the force during the displacement of the block from x=0 at x = 4m

Answer:

The work done by the body is 10 Joules

Explanation :

Given that :

A block of mass 5 kg initially is at rest Aforce of F = ( 20 + 5x ) N is acted on it along the positive x direction along the displacement of x = 0 to x = 4m

ToFind:

The work done on the body

Formula Used :

[tex]\bigstar \; {\underline{\boxed{ {\bf Work \; done}= \int \vec{\bf F . } \vec{\bf dx} }}}[/tex]

Required Solution :

Since a variable force acts upon the body

[tex]\bigstar[/tex] Formula to find the work done

[tex]\leadsto \; {\pink{\boxed{ {\bf Work \; done}= \int\vec{\bf F . } \vec{\bf dx} }}}[/tex]

[tex]\longrightarrow \vec{\sf F} . \vec { \sf dr} = \sf | F | |dx| \cos(\emptyset )[/tex]

[tex]\bigstar[/tex] Here ,

As the force and the displacement are in the same direction the angle between them is 0°  [ Cos ( 0 ) = 1 ]

[tex]\longrightarrow \rm Work \; done = \displaystyle \int^4_0 \rm F . dx[/tex]

[tex]\longrightarrow \rm Work \; done = \displaystyle \int^4_0\rm ( 20+ 5x ) \;dx[/tex]

[tex]\longrightarrow \rm Work \; done = \displaystyle \int^4_0 \rm 20 \; dx + \int^4_0 5x \; dx[/tex]

[tex]\longrightarrow \rm Work \; done = \displaystyle 20 \int^4_0 \rm dx + 5 \int^4_0 x \; dx[/tex]

[tex]\bigstar[/tex] Integrating further,

[tex]\longrightarrow \rm Work \; done = 20 \bigg[ x \bigg]^4_0 + 5 \bigg[ \dfrac{x^2}{2} \bigg]^4_0[/tex]

[tex]\longrightarrow \rm Work \; done = 20 \bigg[ 4 - 0 \bigg]+ 5 \bigg[ \dfrac{4^2- 0^2}{2} \bigg][/tex]

[tex]\bigstar[/tex]Calculating the work done,

[tex]\longrightarrow \rm Work \; done = 20 ( 4) + 5 ( 8 - 0 )[/tex]

[tex]\longrightarrow \rm Work \; done = 20 ( 4) + 5 ( 8 )[/tex]

[tex]\longrightarrow {\red{\underline{\underline{\rm{ Work \; done_{ (on \; the \; particle)}= 120 \; Joules }}}}}[/tex]

Therefore :

The work done on the particle is 120 Joules

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5. The bars of chocolate in a box have total mass of 15/16 kg. Each bar of chocolate has a mass of 5/32 kg. How many bars of chocolate are there in the box?

15/16:5/32=15/16x32/5=480/80=6barstotal mass = 15/16 kg
each bar = 5/32
many bar = total mass ÷ each bar
=15/16 ÷ 5/32
= 15/16 × 32/5
= 480/80
= 6

chocolate are there in the box have 6 bars

6. Ron divided 207 kg of rice into 3 bags, A, B and C, the ratio of the mass of rice in Bag A to the mass of rice in Bag B was 1 : 2. The ratio of the mass of rice in Bag B to the mass of rice in Bag C was 4 : 3. a. Find the ratio of the mass of rice in Bag A to the mass of rice in Bag B to the mass of rice in Bag C. b. Find the mass of rice in Bag A dengan cara ya!!

Jawaban:

a. 2:4:3

b. 46 kg

Penjelasan:

a. A : B = 1 : 2

B : C = 4 : 3

multiply either equation so that both equations have the same value for B. i choose to multiply the first equation by 2. so,

A : B = 2 : 4

since both ratios have the same value for B, we can merge them together.

A : B : C = 2 : 4 : 3

b. mass A = A/total mass x total mass

since we have the ratio for A and the total mass = 2:(2+4+3),

mass A = 2/9 x 207

= 2 x 23

= 46 kg

7. A 5g bullet moving at 100 m/s collides a wooden target, initially at rest. The mass of wooden target is 1kg. If after the collision the bullet is embed in the wooden block, what is the final speed of the wooden block?

This is innelastic collision. so we can use formula:
m1.v1+m2v2=(m1+m2)vf
5x100+1kgx0=(5+1000)vf
500+0=1005Vf
Vf=500/1005=0.49 m/s

8. A bullet of mass 0.20 kg travels horizontally at a speed of 400 m/s. it strikes a stationary wooden block of mass 1.80 kg resting on a frictionless, horizontal surface. the bullet stays in the block. what is the speed of the bullet and the block immediately after the impact? 200 m/s 80 m/s 44 m/s 40 m/s (in ulanganku hari ini)

Jawaban:

40 m/s

Penjelasan:

Known :

Mb = 0.20 kg

Vb = 400 m/s

Mw = 1.8 kg

Vw = 0 m/s (Resting)

Solution :

Because bullet stays in the block, then the speed of the bullet and the block will be same :

Mb . Vb + Mw . Vw = (Mb + Mw) . V

0.2 . 400 + 0 = (0.2 + 1.8) . V

V = 40 m/s

9. Effect of force kicking a moving ball object to another player ? Change the direction or moving faster ?

Jawaban:

Change the direction or moving faster ?

10. The mass of an oxygen atom in (2,7 x 10-21) gram. Determine the mass of oxygen with 8 x 1018 atoms!​

Jawaban:

Testing...

12345

Maap hehe

11. The ball with mass of 0,3 kg at a speed of 10 m/s to the wall, after collision its speed is 50 m/s in the opposite direction. What is the impulse?

I = Δp
  = m(v - v₀)
  = (0,3 kg)(-50 m/s - 10 m/s) = -18 Ns

12. PLS BANGET AKU BUTUH CEPETWhich object has the greatest weight?A. A an object of mass 10 kg in a 15 N / kg gravitational fieldB. B an object of mass 15 kg in a 13 N / kg gravitational fieldC. C an object of mass 20 kg in a 9.0 N / kg gravitational fieldD. D an object of mass 50 kg in a 3.0 N / kg gravitational field

Jawaban:

Jawabannya adalah B

Penjelasan:

Soal tersebut mencari Weight (Berat). Adapun rumusnya adalah W= M×G

Jadi,yang paling berat adalah B karena

W = M×G

W = 15×13

W = 195 Newton.

13. Which of the following would produce the most power? A. A mass of 2 kilograms lifted 10 meters in 10 seconds B. A mass of 5 kilograms lifted 5 meters in 10 seconds C. A mass of 1 kilograms lifted 10 meters in 5 seconds D. A mass of 2 kilograms lifted 10 meters in 5 seconds​

Jawaban:

b.a mass of 5 kilograms lifted 5 meters in 10 seconds

Penjelasan:

maaf kalo salah

Answer:

D

Explanation:

Formula for power: P = W/Δt

Formula for work: W = N.s = m.a.s

Formula for force: F = m.a

Formula for acceleration: a = [tex]\frac{vt-v0}{t}[/tex]

vt = final velocity

v0 = starting velocity

t = time

(edit)

since the questions state how high the item travels in a set period of time, here's how to calculate the speed and acceleration!

for example:

I'll use block A.

Block A traveled 10 meters in 10 seconds, so the speed would be 10 meters divided by 10 seconds, which equates to 1 m/s.

The acceleration would be 1 m/s, which is the final velocity, minus 0, which is the starting velocity, divided by 10 seconds, which is the amount of time required to travel the set distance. So, following the formula, the equation would be a = [tex]\frac{1 - 0}{10 s}[/tex], which equals [tex]\frac{1}{10}[/tex]m/s², or 0.1 m/s².

Using those numbers, we can calculate the amount of force produced, which is F = m.a. Plugging the numbers in, it would be F = 2 kg. 0.1 m/s², which equals 0.2 N.

From here, we just need to calculate the work using W = m.a.s, which calculates to W = 0,2N . 10 m= 2 J, and calculate the amount of power it would generate using P = W/Δt, which calculates to P = 2 J / 10 s, which is the amount of time required to travel the set distance. After all that, we get the equation P = 2 J / 10 s, which equals to 0.2 Watts.

A: Power = F.s/Δt = (2 kg . 1 m²/s²) / 10 s = 0.2 W

B: Power = F.s/Δt = (5 kg . 0.5 m²/s²) / 10 s = 0.25 W

C: Power = F.s/Δt = (1 kg . 2 m²/s²) / 5 s = 0.4 W

D: Power = F.s/Δt = (2 kg . 2 m²/s²) / 5s = 0.8 W

Hence, D would produce the most power.

I'm sorry for the lots of edits. I just felt like there's some explaining to do there!

14. An object has a kinetic energy of 49 J and a mass of 2 kg, how fast is the object moving?

Energi Kinetik

Diketahui:

Ek = energi kinetik = 49 J m = massa = 2 kg

Ditanya:

v = kecepatan ?

Jawaban

Ek = ½ × m × v²

49 = ½ × 2 × v²

49 = 1 × v²

v² = 49/1

v² = 49

v = 7 m/s ✔

15. A mass of 20 kg travels at 7 m/s and collided with a mass of 12 kg. traveling at 20 m/s in the opposite direction along the same line The coefficient of restitution is 0.7. Determine the velocities after collision​

When two objects collide, their kinetic energy, momentum, and velocity can change depending on the type of collision they experience. In the case of an elastic collision, in which the objects bounce off each other without any loss of kinetic energy, the final velocities of the objects can be calculated using the conservation of momentum and the coefficient of restitution.

In an inelastic collision, on the other hand, some of the kinetic energy is converted into other forms of energy, such as heat or sound. This means that the final velocities of the objects will be different from those in an elastic collision.

In your case, since you have provided the coefficient of restitution, it appears that the collision between the two objects is elastic. To determine their final velocities, we can use the following formula:

Final velocity of first object = (initial velocity of first object * (mass of first object - mass of second object) + 2 * mass of second object * initial velocity of second object) / (mass of first object + mass of second object)

Final velocity of second object = (initial velocity of second object * (mass of second object - mass of first object) + 2 * mass of first object * initial velocity of first object) / (mass of first object + mass of second object)

In your case, the initial velocities of the two objects are 7 m/s and 20 m/s, respectively, and the masses are 20 kg and 12 kg. Plugging these values into the above formula, we get the following:

Final velocity of first object = (7 m/s * (20 kg - 12 kg) + 2 * 12 kg * 20 m/s) / (20 kg + 12 kg) = 5.6 m/s

Final velocity of second object = (20 m/s * (12 kg - 20 kg) + 2 * 20 kg * 7 m/s) / (20 kg + 12 kg) = -14.4 m/s

Therefore, the velocities of the two objects after the collision are 5.6 m/s and -14.4 m/s, respectively.

16. 2/3 of the mass of a lobster is equal to 3/8 of the mass of a king crab. the difference in their masses is 7/10 kg. what is the mass of the king crab?

Jawab:

1.6 kg

Penjelasan dengan langkah-langkah:

Let : Mass of a lobster = L

        Mass of a king crab = K

         

So :

[tex]\frac{2}{3} L = \frac{3}{8} K\\\\L = \frac{3}{8} K \ x \ \frac{3}{2} = \frac{9}{16} K\\\\K > L, so\\\\K - L = \frac{7}{10} \\\\K - \frac{9}{16} K = \frac{7}{10}\\\\\frac{7}{16} K = \frac{7}{10}\\\\K = 1.6 kg[/tex]

17. The ball with mass of 0.1 kg moving at a speed of 20 m/s, the stick hits it with a force of 1.000 N in the opposite direction so that its speed becomes 40 m/s². what is the duration of stick touches the ball?

MOMENTUM

m = 0,1 kg
Vi = 20 m/s
Vt = - 40 m/s
F = - 1000 N
t = __?

I = ∆p
F t = m (Vt - Vo)
-1000 t = 0,1 (-40 - 20)
-1000 t = -6
t = 6/1000 s ← ans
The unit of velocity is m/s !
I = Δp
FΔt = m(v - v₀)
Δt = m(v - v₀) / F
     = (0,1 kg)(-40 m/s - 20 m/s) / (-1000 N) = 6 x 10⁻³ s

18. The mass of 5 equal steel balls is 8 kg. Calculate the mass, in kg of 4 steel balls.​

Jawab:

6,4 kg

Penjelasan dengan langkah-langkah:

5 steel balls = 8 kg

1 steel ball = 8 : 5 = 1,6 kg

so, 4 steel balls = 4 x 1,6 kg = 6,4 kg

19. The total mass of 12 bottles of juice and 11 bottles of syrup was 30.9 kg. The total mass of 3 bottles of juice and 3 bottles of syrup was 8.1 kg. Find the mass of a bottle of syrup. (In KG)

Jawaban:

1, 5 kg

Penjelasan dengan langkah-langkah:

bottles of juice = x

bottle of syrup = y

12x + 11y = 30.9

3x + 3 y = 8,1 (4)

jadi

12x + 11 y = 30.9

12x + 12y = 32.4

eliminasi

-y = -1.5 kg

y = 1.5 kg

20. The total mass of a block of butter and a box of cherries is 384 g. The mass of theblock of butter is twice the mass of the box of cherries. Find the mass of the blockof butter.​

draw model: ∆∆∆

384÷ 3 = 128

cherries = 128 g

butter = 2x 128

butter = 256 g

_____

semangat belajar....