1) ( x^2 + 2x - 5 ) + ( 3x - 2 ) = 2) ( 2x + 3 ) - (-2x - 4 ) = 3) 3( x^2 - 3x ) = 4) ( x + 5 ) ( x - 5 ) = 5) ( 2x + 3 ) ( x - 5 ) =

1. 1) ( x^2 + 2x - 5 ) + ( 3x - 2 ) = 2) ( 2x + 3 ) - (-2x - 4 ) = 3) 3( x^2 - 3x ) = 4) ( x + 5 ) ( x - 5 ) = 5) ( 2x + 3 ) ( x - 5 ) =

[tex]Penyelesaian : 1) ( x^{2} + 2x - 5 ) + ( 3x - 2 ) = x^{2} + 2x - 5 + 3x - 2 = x^{2} + 5x - 7 2) ( 2x + 3 ) - ( -2x - 4 ) = 2x + 3 + 2x + 4 = 4x + 7 3) 3( x^{2} - 3x ) = 3 x^{2} - 9 x^{2} 4) ( x + 5 ) ( x - 5 ) = x^{2} - 5x + 5x - 25 = x^{2} - 25 5) ( 2x + 3 ) ( x - 5 ) = 2 x^{2} - 10x + 3x - 15 = 2 x^{2} - 7x - 15[/tex]

2. 1. |x - 2|=2. |x - 3| + 5=3. |2x + 1| - 2=4. 3 |x - 1|=5. |2x + 1| - x=6. |2 - x| + 7=​

Jawaban:

maksud apa ya tolong jawab ?? pliss jawab

3. Invers dari f(x) = (5x -3)/(x - 2), x ≠ 2 adalah ... (2x -3)/(x - 5), x ≠ 5 (-2x -3)/(x - 5), x ≠ 5 (5x -3)/(x - 2), x ≠ 2 (-3x + 5)/(-2x +1), x ≠ 1/2 (-5x +3)/(-x + 2), x ≠ 2

(2x-3)/(x-5),
Kalo ga salah Kelas 10 Matematika
Bab Fungsi Komposisi

f(x) = (ax + b)/(cx + d)
f⁻¹ (x) = (-dx + b)/(cx - a)

f(x) = (5x - 3)/(x - 2)
f⁻¹ (x) = (2x - 3)/(x - 5)

di mana x ≠ 5

4. 3(2x+5)=2x-1 2(x+2)=3(x-7)

6x+15=2x-1
4x=-16
x=-4
2x+4=3x-21
-x=-25
x=253(2x+5)=2x-1
6x+15=2x-1
6x-2x=-1-15
4x = -16
x = -4

2(x+2)=3(x-7)
2x+4=3x-21
2x-3x=-21-4
-x = - 25
x = 25

5. 1.(x-7)=22.(2x-5)=73.(3-2x)+5=54(2x+4)per(x-1)=1​

Jawaban:

1. 9

2.6

3.-1,5

4.-4

Penjelasan dengan langkah-langkah:

1.(x -7) = 2

x = 2+7

x. = 9

2. ( 2x -5) = 7

2x. = 7+5

2x. = 12

x. = 12/2

x. = 6

3. (3-2x) +5 = 5

-2x= 5-5-3

-2x = -3

x = -3/2

x = -1/5

4.( 2x + 4) / (x - 1) = 1

kita jadikan satu...

(2x+4) - ( x -1)= 1

2x+4-x+1=1

2x-x= 1-1-4

x. = -4

SEMOGA MEMBANTU

6. Bentuk sederhana dari 1.) -(x+5)-3(x²-2x+1) 2.) 3(2x²+x-2)-5(x²+3)

[tex]-(x+5)-3( x^{2} -2x+1) \\ =-x-5-3 x^{2} +6x-3 \\ =-3 x^{2} +5x-8 \\ =3 x^{2} -5x+8[/tex]


[tex]3(2 x^{2} +x-2)-5( x^{2} +3) \\ =6 x^{2} +3x-6-5 x^{2} -15 \\ = x^{2} +3x-21[/tex]

7. l. 3(2x-1)=2. -2(×+8)=3.(x-2) (x-1)=4.(2x + 1) (x-1)=5.(x+3) (x+2)=​

Jawaban:

3(2x-1) = 6x - 3

-2(x+8) = -2x - 16

(x-2)(x-1) = x^2 - 2x - x + 2

= x^2 - 3x + 2

(2x+1)(x-1) = 2x^2 + x - 2x -1

= 2x^2 - x - 1

(x+3)(x+2) = x^2 + 3x + 2x + 6

= x^2 + 5x + 6

Jawaban:

1. 3(2x-1)= 6x-3

2. -2(x+8)= -2x-16

3. (x-2)(x-1)= x2-x-2x+2

4. (2x+1)(x-1)= 2x2-2x+x-1

5. (x-3)(x+2)= x2+2x-3x-6

itu maksud x2 itu x kuadrat, begitu juga yang lainnya.

Jangan lupa klik terima kasih yaa

8. 1 . (X +5) (5x-1)2. (7-2X) (2X-7)3. (2x-3) (x+5)4. (X+2) (X+3)5. (x+3) (x-1)​

Jawaban:

1.x -5x = -5 - 1

-4x = -6

x = 3/2

Penjelasan dengan langkah-langkah:

Gitu tah caranya,sefaham ku gitu klok bener nanti tak lanjutin

Jawaban:

terlampir

Penjelasan dengan langkah-langkah:

semoga membantu dan benar. amin

9. 1. (4x - 2) - (2x - 4) = 2. (3x + 2) - (2x - 1) =3. (3x - 3) + (2x - 1) =4. (x+2) + (x+2) = 5. (2x + 2) + (x + 3) = ​

Materi : Bentuk Aljabar

Soal Nomor 1

4x - 2 -( 2x - 4 )

4x - 2 - 2x + 4

( 4 - 2 )x + 2

2x + 2

Soal Nomor 2

3x + 2 -( 2x - 1 )

3x + 2 - 2x + 1

( 3 - 2 )x + 3

x + 3

Soal Nomor 3

3x - 3 + 2x - 1

( 3 + 2 )x - 4

5x - 4

Soal Nomor 4

x + 2 + x + 2 )

( 1 + 1 )x + 4

2x + 4

Soal Nomor 5

2x + 3 + x + 3

( 2 + 1 )x + 6

3x + 6

Semoga bisa membantu

[tex] \boxed{ \colorbox{lightblue}{ \sf{ \color{blue}{ Answer By\:BlueBraxGeometry}}}} [/tex]

1. (4x - 2) - (2x - 4)

= 4x - 2 - 2x + 4

= 4x - 2x - 2 + 4

= 2x + 2

2. (3x + 2) - (2x - 1)

= 3x + 2 - 2x + 1

= 3x - 2x + 2 + 1

= 1x + 3

= x + 3

3. (3x - 3) + (2x - 1)

= 3x - 3 + 2x - 1

= 3x + 2x - 3 - 1

= 5x - 4

4. (x+2) + (x+2)

= x + 2 + x + 2

= x + x + 2 + 2

= 2x + 4

5. (2x + 2) + (x + 3)

= 2x + 2 + x + 3

= 2x + x + 2 + 3

= 3x + 5

10. 1.(x+3) (x-2) =2.(x-5) (x-3) =3.(x+2) (2x-1) =4.(2x-3) (x+-1) =5.(x+4) (2x-1) =6.(2x-3) (x-2) =7.(3x+1) (2x+3) =8.(2x-1) (2x+3) =9.(2x+3) (x+2y-3) =10.(3-2x) (1+3x) =Tolong jawab ya... ​

semoga membantuuuuuuu^^

11. Contoh1 Tentukan hp dari | 2x + 3 | ≤ 5Jwb-5 ≤ 2x +3. ≤ 5-5 -3 ≤ 2x. ≤ 5 -3- 8 ≤ 2x ≤ 2-8/2 ≤ x. ≤ 2/2-4. ≤ x ≤ 1​

Jawaban:

Hp : {x | x -4 ≥ x ≥ 1}

Penjelasan dengan langkah-langkah:

Ada pada lampiran

12. 5/2x + 3/2x= 3/(x+2) + 2/(x-3)= 4/x+3 - 5/x-1=

Jawaban:

Maaf kalau jawabannya salah, terima kasih

13. tlng bantu saya kerja soal ini ya... 1.(x^2+5x+5)(2x^2-x) 2.(6x^2+x-1) (x+2) (x-1) 3.(x+2) (x-5) (2x+3) 4. 3x (-2x+1) (3-2x) (4+x)

1. 2x^4 + 9x^3 + 5x^2 -5x
2. 6x^4 + 7x^3 - 12x^2 - 3x + 2
3. 2x^3 - 3x^2 - 19x^2 - 30
4. 6x^3 + 15x^2 -36x

14. Persamaan nilai mutlak 1. |2x-1| = x-1 2. |3x-2| = 2x-2 3. |3x+1| = 2x 4. |x-1| = 3x+3 5. |2x+5| = x-2 6. |3x-5| - x = 2

Jawaban:

56 56 tdbsbsjwnsnsjaiw wwjwooekehdhdhvd f fbdnjdjrkrrndnndjxhgbf gjcjcjcngnofprmrorirhydytwgwbw x x bxjxnfnfjkxnfnr rntigijhjgideloerirthnw smmsbbxb xn gatau hehe

15. Persamaan nilai mutlak 1.) |2x-1| = x-1 2.) |3x-2| = 2x-2 3.) |3x+1| = 2x 4.) |x-1| = 3x+3 5.) |2x+5| = x-2 6.) |3x-5| - x = 2

Jawaban:

1. 2x-x=-1+1

3x=0

x=-3

2. 3x-2x=-2+2

x=0

3. 3x-2x=1

x=1

Penjelasan dengan langkah-langkah:

maaf ya kalau salah kak

16. Tentukan nilai x yang memenuhi persamaan Tentukan himpunan penyelesaiannya! 1.) |x| + |x+2| = 4 2.) |x-1| + |x+3| = 5 3.) |2x-1| + |3x-2| = 3 4.) |x+2| + |2x-3| = 4 5.) |x-2| + |5-2x| = 2 6.) |x+1| + |2x| + |3x-5| =7

1) | x| + | x+2| = 4
x> 0 , x+2 > 0
x + x + 2 = 4
2x = 2
x = 1

x < 0 , x +2 < 0
-x - x - 2 = 4
-2x = 6
x = -3

2) |x-1| + |x +3| = 5
x -1 + x + 3 = 5
2x = 3
x = 3/2

x-1 <0 , x+3 < 0
-x + 1 - x - 3 = 5
-2x - 2 = 5
x = - 72

3) |2x -1| + |3x -2| = 3
2x -1 > 0 , 3x -2 > 0
2x -1 + 3x - 2 = 3
5x -3 = 3
x = 6/5

2x-1 < 0 , 3x -2 < 0
1-2x  + 2 - 3x = 3
-5x+3= 3
x = 0

4) |x+2| + |2x-3| = 4
x + 2 + 2x - 3 = 4
3x - 1= 4
x= 5/3

-x - 2 - 2x + 3 = 4
-3x + 1 = 4
x = 1

5) |x -2| + |5 - 2x| = 2
x - 2 + 2x - 5 = 2
3x - 7 = 2
x = 3

2 - x + 5 - 2x = 2
-3x + 7 = 2
x = 5/3

6) |x+1| +|2x| + |3x -5| = 7
|x+1| + 2|x| + |3x -5| = 7
x+1 + 2x+ 3x - 5 = 7
6x - 4 = 7
x = 11/6

x + 1 - 2x -3x + 5 = 7
-4x + 6 = 7
x = -1/4

17. 3^2x-2=5^x-1[tex] {3}^{2x - 2} = {5}^{x - 1} [/tex]

Matematika
Bab: Eksponensial dan Logaritma
Kelas: XII SMA
=================
3^2x-2 = 5^x-1
Tarik logaritma dari kedua sisi:
3 log 3 (2x-1) = 3 log 5(x-1)
2x-2= x-1(3log5)
2x-2 = (3log 5 x) - 3 log 5
Pindahkan ke sisi yg sesuai dgn variabel
2x - (3 log5)x = -3log5 + 2
(2-3log5)x = -3log5 +2
x = -3log5 +2 / 2-3log5
x = 1

18. 1)2x² x -2 + 1= 2)2x² x -1 +1= 3)2x² x 0 + 1= 4)2x² x 1 +1= 5)2x² x 2 +1= 6)2x² x 3 +1=

1. 2x² × -2 + 1 = -4x² + 1
2. 2x² × -1 + 1 = -2x² + 1
3. 2x² × 0 + 1 = 1
4. 2x² × 1 + 1 = 2x² + 1
5. 2x² × 2 + 1 = 4x² + 1
6. 2x² × 3 + 1 = 6x² + 1
Sorry kalo ada yang salah. :)1)2x² x -2 +=-4x²+1
2)2x² x -1 +1=-2x²+1
3)2x² x 0 +1=1
4)2x² x 1 +1=2x²+1
5)2x² x 2 +1=4x²+1
6)2x² x 3 +1=6x² +1

19. 3.(x+2)(2x+3) 4.(2x-3)(x+3) 5.(x-3)(x+3) 6.(x+3)² 7.(x+2)(x-2 8.(2x+5)(2x-5) 9.(2x-1)² 10.(-2x+1)(2x+1) Perkalian aljabar tlg dgn caranya juga

3) (x + 2)(2x + 3) = 2x² + 3x + 4x + 6
= 2x² + 7x + 6

4) (2x - 3)(x + 3) = 2x² + 6x - 3x - 9
= 2x² + 3x - 9

5) (x - 3)(x + 3) = x² - 9

6) (x + 3)² = x² + 6x + 93) (x+2)(2x+3) = 2x² + 3x + 4x + 6 = 2x² + 7x + 6
4) (2x-3)(x+3) = 2x² + 6x - 3x -9 = 2x² + 3x -9
5) (x-3)(x+3) = x² + 3x - 3x -9 = x² -9
6) (x+3)² = (x+3)(x+3) = x² + 3x + 3x + 9 = x² + 6x + 9
7) (x+2)(x-2) = x² - 2x + 2x - 4 = x² - 4
8) (2x+5)(2x-5) = 4x² - 10x + 10x - 25 = 4x² - 25
9) (2x-1)² = (2x-1)(2x-1) = 4x² - 2x - 2x + 1 = 4x² - 4x + 1
10)(-2x+1)(2x+1) = - 4x² - 2x + 2x + 1 = 4x² + 1 ..
priksa kmbali

20. 1. |x-3|_<3 2. |2x-5|_>7 3. |4x-2|<1 4. |2x-1|>|x+2| 5. |x+4|_<|2x-6|

Jawaban:

klahlt heh wiubjegv habn jhw hecbj hav Dhe wik ahhh jhw vvsvhv the yahhh ahhh wikk