2. A rubber ball is dropped onto the floor from a height of ℎ metres. The time taken for it to stop bouncing is t seconds. This is given by the formula, where is a number that measures the ‘bounciness’ of the rubber ball. When dropped from a height of 1.25 m, it bounces for 2.5 s. a. Find the value of e b. For how long would the rubber ball bounce if it was dropped from a height of 1.8 m? c. The same rubber ball is dropped again, and this time it bounces for 3.5 s. find the height that it was dropped from.

1. 2. A rubber ball is dropped onto the floor from a height of ℎ metres. The time taken for it to stop bouncing is t seconds. This is given by the formula, where is a number that measures the ‘bounciness’ of the rubber ball. When dropped from a height of 1.25 m, it bounces for 2.5 s. a. Find the value of e b. For how long would the rubber ball bounce if it was dropped from a height of 1.8 m? c. The same rubber ball is dropped again, and this time it bounces for 3.5 s. find the height that it was dropped from.

a. [tex]t=(\frac{1+e}{1-e})\sqrt{\frac{h}{5}}\\2,5=(\frac{1+e}{1-e})\sqrt{\frac{1,25}{5}}\\2,5=(\frac{1+e}{1-e})\cdot0,5\\\frac{2,5}{0,5}=\frac{1+e}{1-e}\\5-5e=1+e\\6e=4\\e=\frac{4}{6}\\[/tex]

b. & c. just substitution the variable

Good luck

2. a ball with a mass of 2 kg is dropped from the top of a building and strikes the ground at a velocity of 10 m/s what is the heigt of the building from which the ball is dropped?

Materi : Kinematika Gerak Lurus
Sub materi : Gerak Jatuh Bebas
Mapel : Fisika
Kelas : X SMA (KTSP)
Keyword : GJB

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Diketahui :
m = 2 kg
v = 10 m/s

Ditanya :
h = ?

Penyelesaian :
Gerak jatuh bebas merupakan gerak benda dengan kecepatan awal benda Vo = 0 ,bisa dikatakan benda jatuh secara spontan.

Analisis soal :
A ball with a mass m kg dropped from the building which the height h meter. When the ball strikes, the velocity is 10m/s. The problem is what is the height of the building where the ball was dropped from?

Perhitungan :
v = √2gh
v² = 2gh
(10)² = 2(10)h
100 = 20h
h = 100/20
h = 5 m

So, the height of the building where the ball was dropped from is 5 m

-vin

3. A stone is dropped from a height of 5 metres. What is the speed of the stone just before the stone reaches the floor? [gravitational acceleration = 10ms-²]​

Jawaban:

see the answer in the image attached. thanks

Penjelasan:

4. A ball is thrown vertically upwards and reaches its maximum height 2.0 s later a. What is the initial velocity of the ball? b. What is the maximum height that the ball reaches?

Given : Time taken to reach the maximum height t=2 s

a=−g=−10m/s ^2

The initial velocity of the ball can be calculated by,

Using v=u+at

∴ 0=u−10×2 ⟹u=20 m/s

Using S = ut + 1/2at^2

S = 20.2 + 1/2 (-10)(2)^2

S = 40 + (-20)

S = 20m (the maximum height)

5. one stone is dropped from the side of a bridge and a second is dropped from the same place a short time later. what do you think about the distance between the stones as a function of time after both have been dropped ? ignore air resistance

satu batu dijatuhkan dari sisi jembatan dan yang kedua dijatuhkan dari tempat yang sama beberapa saat kemudian. apa pendapat Anda tentang jarak antara batu-batu itu sebagai fungsi waktu setelah keduanya dijatuhkan? abaikan hambatan udara

maaf ya aku cuma tau artinya

6. Tolong dijawab kak A ball is kicked at an angle of 37° with the ground. Determine the initial velocity of the ball so that it hits a target that is 32 m away at a height of 4 m.

Jawaban:

20 m/s

Penjelasan:

Sx = V0x . t

32 = V0 . cos 37° . t

t = 32 / V0 . cos 37°

t = 32 / V0 . 4/5

t = 40 / V0

V0y = V0 . sin 37°

V0y = 3/5 V0

Sy = V0y . t + 1/2 g . t²

4 = (3/5 V0) . (40 / V0) + 1/2 . (-10) . (40 / V0)²

4 = 24 - 5 (40 / V0)²

- 20 = - 5 (40 / V0)²

(40 / V0)² = -20/-5

(40 / V0)² = 4

40 / V0 = 4

40 = 2 V0

V0 = 20 m/s

7. a sepak takraw that is kicked from a height of two meters?

Jawaban:

sebuah sepak takraw yang ditendang dari ketinggian dua meter?

8. A ball with a mass of 200g is placed on a compressed spring. The spring is then released and the ball bounces up. The compressed spring has 5 3 of elastic potential energy. : (a) Calculate the speed of the ball immediately when the ball bounces up. (b) What is the height that can be reached by the ball from the position it was released? [gravitational acceleration = 10ms ³]soal A nya saja please​

Jawaban:

Gk tau

Penjelasan:

Gk bisa bahasa inggris :v

9. Cricket is from the United Kingdom._____________________________a. It's from United Kingdomb. It's British​

Jawaban:

A. it's from United Kingdom

Maaf kalo salah :)

10. a warter reservoir at a height of 1.2 m is full of water. at the height of 90 cm from the water

90 cm = 0,09 m
12 m-0,09 m = 1,11 m

11. A ball A is thrown vertically upward from the top of a 30-m-high building with an initial velocity of 5 m/s. At the same instant another ball B is thrown upward from the ground with an initial velocity of 20 m/s. Determine the height from the ground and the time at which they pass.

Jawab:

Penjelasan dengan langkah-langkah:

12. a sepak takraw that is kicked from a height?

Jawaban:

A sepak takraw that is kicked from a height of two meters?

Penjelasan:

13. You drop a ball from a height of 2.0 m, and it bounces back to a height of 1.6 m. (a) What fraction of its initial energy is lost during the bounce? (b) What is the ball’s speed just before and just after the bounce? (c) Where did the energy go?

Jawaban sudah saya tulis di atas.

14. 0 Predict whether the ping pong ball will stay close to or separate from the golf bal if the balls are stacked together and dropped from a height. Explain your prediction.​

Prediksilah apakah sebuah bola ping pong akan tetap berdampingan atau berpisah dari sebuah bola golf jika kedua bola ditumpuk bersama dan dijatuhkan dari sebuah ketinggian. Jelaskan prediksi anda.

Sebuah bola ping pong akan tetap berdampingan dengan sebuah bola golf jika kedua bola ditumpuk bersama dan dijatuhkan bebas dari sebuah ketinggian.

Penjelasan:

Sebelum membahas kesimpulan dari eksperimen Gerak Jatuh Bebas kedua bola di atas, berikut asumsi kondisi:

1. Mengabaikan gaya gesek bola dan gaya hambat udara.

2. Kedua bola dijatuhkan bebas dari kondisi diam (tanpa ada tambahan kecepatan awal).

Ketika kedua bola dijatuhkan bebas bersamaan dengan kedua asumsi di atas maka kedua bola akan jatuh bebas ke bumi dalam waktu bersamaan. Hal ini dikarenakan percepatan gravitasi bumi adalah sama untuk kedua bola tersebut saat jatuh bebas.

Dalam rumus ilmu Fisika Gerak Jatuh Bebas dapat digambarkan sebagai berikut:

Misalkan:

    Berat bola golf = m(golf) = 50 grams

    Berat bola ping pong = m(pingpong) = 5 grams

    Percepatan gravitasi = g = 10m/s2 (dibulatkan untuk simplifikasi perhitungan).

Rumus Gaya Gerak Jatuh Bebas:

    F = m x g

    F(golf) = m(golf) x g

                       = 50 x 10 = 500N

    F(ping pong) = m(ping pong) x g

                       = 5 x 10 = 50N

Ratio Gaya Gerak Jatuh Bebas (F) terhadap Masa (m) yang terjadi pada kedua bola tersebut akan tetap konstan, yaitu:

    F(golf) / m(golf) = 500/50 = 10m/s2 = g

    F(pingpong) / m(ping pong) = 50/5 = 10m/s2 = g

Dari rumus di atas, kedua bola akan berakselerasi dengan kecepatan dan waktu yang sama saat menyentuh permukaan bumi yang menurut rumus Gerak Jatuh Bebas:

    Kecepatan = gravitasi x waktu

                 V   = g x t

Pelajari lebih lanjut:

Penjelasan dan rumus Gerak Jatuh Bebas https://brainly.co.id/tugas/6956936

Penjelasan Gerak Jatuh Bebas dan contoh https://brainly.co.id/tugas/5870035

#BelajarBersamaBrainly

15. Physics IGCSE 0625/21/M/J/18 A ball of mass 1.2 kg is deopped from a height of 30 m. As it falls, 25% of its initial gravitational potential energy is transferred to thermal energy. What is the kinetic energy of the ball just before it hits the ground?

Jawaban:

Energi potensial (Ep)

Ep = mgh

= 1,2×10×30

= 12×30

= 360 J

Karena ada energi yang hilang (thermal energy), maka tidak ada konservasi energi

E thermal = 25% Ep

= 1/4 Ep

= 1/4×360

= 90 J

Ep = E thermal + Ek

360 = 90 + Ek

Ek = 270 J

Jawaban:

the kinetic energy of the ball just before it hits the ground is 270 Joule.

Penjelasan:

Conservation of mechanical energy states that the total energy of the system remains constant.

before the ball dropped, it has its potential energy defined by

Ep = m.g.h = (1.2)(10)(30) = 360 Joule

the kinetic energy is zero since the ball is at rest.

and when the ball hits the ground, the potential energy is zero while the kinetic energy becomes maximum.

since 25% of its initial potential energy is transferred to thermal energy, then the remaining potential energy is only 75%, it is 75% of 360 Joule = 270 Joule, and this is the only amount of energy that can be converted into kinetical energy then.

Therefore, the kinetic energy of the ball just before it hits the ground is 270 Joule.

Hopefully this is understandable and helpful.

Thank you

#TetapBelajar

#TetapSehat

#TetapJagaKesehatan

16. a sepak takraw that is kicked from a height of two meters follows a path that is?

Jawaban:

sebuah sepak takraw yang ditendang dari ketinggian dua meter mengikuti jalan setapak itu?

17. A ball is thrown vertically upwards and reaches its maximum height 2.0 s later a. What is the initial velocity of the ball? b. What is the maximum height that the ball reaches?

Jawaban:

a. 20m/s

b.20m

Penjelasan:

Given : Time taken to reach the maximum height t=2 s

a=−g=−10m/s ^2

The initial velocity of the ball can be calculated by,

Using v=u+at

∴ 0=u−10×2 ⟹u=20 m/s

Using S = ut + 1/2at^2

S = 20.2 + 1/2 (-10)(2)^2

S = 40 + (-20)

S = 20m (the maximum height)

18. A ball is dropped from a height and hits the floor with a speed of 10 m/s. Then the ball bounces up with a speed of 4 m/s. Calculate: a. Impulse acting on the ball if the ball has a mass of 0.2 kg (20 poin)b. The force acting on the floor when the ball hits the floor for 0.01 second (20 poin)​

Jawaban:

Penjelasan:

a. impulse acting to the ball is equal with the change of linear momentum

[tex]I=-\Delta P=-m(v_2-v_1)=-0.2kg(4m/s-10m/s)=7.2Ns[/tex]

b. the average force acting on the floor

[tex]I=F\Delta t=7.2 Ns=F(0.01s)\\F=720N[/tex]

19. A stone is dropped from the roof of a tall building of height 40m .what is the distance the stone fell through 1 second before it hits the ground ?Assume that the stone falls from rest and air resistance is neglected​

Jawaban:

Distance the stone fell through 1 second before it hits the ground is 19,25 m.

Penjelasan:

Known =

h = high = 40 m

Assumed acceleration due to gravity (g) = 10 m/s²

Asked :

S = distance the stone fell through 1 second before it hits the ground = ....

Answer :

time  for the stones fall to the ground

[tex]\boxed{t=\sqrt{\frac{2h}{g}}}[/tex]

[tex]t=\sqrt{\frac{2\times40}{10} }[/tex]

[tex]t=\sqrt{\frac{80}{10}}[/tex]

[tex]t=\sqrt{8}[/tex]

t = 2,83 s

distance the stone fell through 1 second before it hits the ground :

t = 2,83 - 1

t = 1,83

[tex]S=\frac{1}{2}gt^2[/tex]

[tex]S=\frac{1}{2}\times10\times1,83^2[/tex]

[tex]S=\frac{1}{2}\times10\times3,35[/tex]

S = 19,25 m

Learn more the materi in :

Materi Tentang Gerak vertikal sebuah batu yang dijatuhkan dari ketinggian h : https://brainly.co.id/tugas/24873060

#BelajarBersamaBrainly

20. what's is the of, •A stove.......•A fork.......• A blanket.......•A cricket.....​

Jawaban:

a.form

Penjelasan:

ya mau membantu